Factoring X2+1
In my high school algebra class I was taught that I could not factor the formula X2+1; that is, that I could not represent it as a product of two formulae as I could with the similar formula
![]()
(Eq
'n 1)While factoring a formula does not actually solve an equation, it is nonetheless a part of the puzzle of algebra because it provides us with one of the tools that we use in solving equations. That equation does, in fact, suggest a way to factor x2+1. We need only recall to mind the fact that multiplying two negative numbers together yields a positive number; that is we can represent any positive number as the negative of a negative number, so we have

(Eq
'n 2)in which
. Of
course that only works if we are allowed to use complex numbers.
Suppose we restrict our factors to real numbers only. Can we still factor x2+1?
We know that we cannot devise a pair of real-valued binomials whose product equals x2+1. Could we devise a pair of real-valued trinomials that will work? In that case we would have

(Eq
'n 3)We easily make the identifications A=x and C=1, so we must have
![]()
(Eq
'n 4)We solve that readily for
and get
![]()
(Eq
'n 5)That particular factorization comes in handy in solving the
integral
.
efefhghgefef